9p^2+23p-12=(9p-4)(p+3)

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Solution for 9p^2+23p-12=(9p-4)(p+3) equation: 



9p^2+23p-12=(9p-4)(p+3)

We move all terms to the left:

9p^2+23p-12-((9p-4)(p+3))=0

We multiply parentheses ..

9p^2-((+9p^2+27p-4p-12))+23p-12=0



We calculate terms in parentheses: -((+9p^2+27p-4p-12)), so:

(+9p^2+27p-4p-12)

We get rid of parentheses

9p^2+27p-4p-12

We add all the numbers together, and all the variables

9p^2+23p-12

Back to the equation:

-(9p^2+23p-12)



We add all the numbers together, and all the variables

9p^2+23p-(9p^2+23p-12)-12=0

We get rid of parentheses

9p^2-9p^2+23p-23p+12-12=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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